Quote:
Originally Posted by feilong  Example
Your Hand = A(d) K(d)
Flop = 10(d) J (d) 2(h)
In this situation you can see that right now you do not have a winning hand. It is safe to assume that if any diamond comes up you will win with a flush. It is also safe to assume that if any queen comes up you will win with a straight.
Outs = 17 (13 Diamonds, 4 Queens)
This means on the flop you will have a 69% chance of winning this hand
17 outs X 4 = 68 + 1 = 69%
On the turn you will have a 35% chance of winning this hand
17 outs X 2 = 34 + 1 = 35 |
I just noticed a problem here. This math is wrong. it is not accoutning for the fact that you are holding 2 diamonds and that out of the four queens one is a diamond as well. Your true outs are 12. The 9 diamonds and 3 queens still left in the deck. The math here is totally wrong.
